## Rung Kutta 4 in more than 1 dimension of space

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AlternateGravity
Posts: 75
Joined: Thu May 15, 2014 5:45 pm

### Rung Kutta 4 in more than 1 dimension of space

I understand that for one dimension of space a Rung Kutta 4 Formula for approximating the equations of motion given some force that depends only on the location of an object is

k1xn=vn
k2xn=vn+h*k1vn/2
k3xn=vn+h*k2vn/2
k4xn=vn+h*k3vn
xn+1=xn+h/6(k1xn+2*k2xn+2*k3xn+k4xn)

k1vn=f(xn)=acceleration
k2vn=f(xn+h*k1xn/2)
k3vn=f(xn+h*k2xn/2)
k4vn=f(xn+h*k3xn)
vn+1=vn+h/6(k1vn+2*k2vn+2*k3vn+k4vn)

h=Deltat

I tried using the above formula with the initial values being x=1, and v=0, the acceleration being given by the equation F=-x, and h=0.3. Rung Kutta verses Analytic.png (206.39 KiB) Viewed 2779 times
and found that the Rung Kutta 4 approximation is close to the analytical solution of x=cos(t) even after nearly 3000 time steps despite having such a large time step.

For comparison when I used the same initial conditions, same equation for acceleration, and same time step law, using a method where I approximate the differential equation using polynomials of the same degree as the order of differential equation, which I will just call the polynomial method in this thread, using the formulas

xn+1=1/2anh^2+vnh+xn
vn+1=anh+vn Polynomial Method.png (279.07 KiB) Viewed 2779 times
The amplitude is already several times greater than that of cosine after only a few cycles.

I also tried using both the Rung Kutta 4 method and the polynomial method mentioned above to approximate the case where the initial position is 1, initial velocity is 0, and with a=sin(x). Rung Kutta verses Polynomial Simple.png (351.78 KiB) Viewed 2779 times
For a time step of 0.006 I found that both formulas give nearly the same result even after nearly 3000 time stems.
Gravitons would be my favorite particle as their existence could prove extra dimensions.

AlternateGravity
Posts: 75
Joined: Thu May 15, 2014 5:45 pm

### Re: Rung Kutta 4 in more than 1 dimension of space

I tried changing the time step to 0.3 Polynomial.png (269.32 KiB) Viewed 2778 times
and found that with the polynomial method the x value doesn't even complete 1 cycle before rushing towards negative infinity Rung Kutta.png (138.39 KiB) Viewed 2778 times
However for the Rung Kutta 4 method the amplitude is nearly the same as it was at the beginning implying that the Rung Kutta method I chose is more accurate than the polynomial method.

I know that for the polynomial method I mentioned the way to extend the method to two spatial dimensions is to use the formula

F=r/||r||*f(||r||)

So I though I could just change the formulas in the Rung Kutta 4 method to

k1rn=vn
k2rn=vn+h*k1vn/2
k3rn=vn+h*k2vn/2
k4rn=vn+h*k3vn
rn+1=rn+h/6(k1rn+2*k2rn+2*k3rn+k4rn)

k1vn=rn/||rn||*f(||rn||)
k2vn=rn+h*k1vn/2/||rn+h*k1vn/2||*f(||rn+h*k1vn/2||)
k3vn=rn+h*k2vn/2/||rn+h*k2vn/2||*f(||rn+h*k2vn/2||)
k4vn=rn+h*k3vn/||rn+h*k3vn||*f(||rn+h*k3vn||)
vn+1=vn+h/6(k1vn+2*k2vn+2*k3vn+k4vn)

I tried this approach on the inverse square law Rung Kutta verses Polynomial 2d.png (355.92 KiB) Viewed 2778 times
And found that the method I chose gave a worse answer than the polynomial method I mentioned making me think I chose the wrong way to generalize the Rung Kutta 4 method as it should be more accurate than the polynomial method I mentioned.

What is the correct way to generalize the Rung Kutta 4 method to more than 1 dimension of space?
Gravitons would be my favorite particle as their existence could prove extra dimensions.

AlternateGravity
Posts: 75
Joined: Thu May 15, 2014 5:45 pm

### Re: Rung Kutta 4 in more than 1 dimension of space

Nevermind, it seems I had the correct formula and the inaccuracies must have been from careless mistakes.
Gravitons would be my favorite particle as their existence could prove extra dimensions.

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